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0=2x^2+15x+7
We move all terms to the left:
0-(2x^2+15x+7)=0
We add all the numbers together, and all the variables
-(2x^2+15x+7)=0
We get rid of parentheses
-2x^2-15x-7=0
a = -2; b = -15; c = -7;
Δ = b2-4ac
Δ = -152-4·(-2)·(-7)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-13}{2*-2}=\frac{2}{-4} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+13}{2*-2}=\frac{28}{-4} =-7 $
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